0.04x^2-1.0476x+0.01416=0

Solution for 0.04x^2-1.0476x+0.01416=0 equation:

0.04x^2-1.0476x+0.01416=0

a = 0.04; b = -1.0476; c = +0.01416;
Δ = b2-4ac
Δ = -1.04762-4·0.04·0.01416
Δ = 1.09520016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.0476)-\sqrt{1.09520016}}{2*0.04}=\frac{1.0476-\sqrt{1.09520016}}{0.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.0476)+\sqrt{1.09520016}}{2*0.04}=\frac{1.0476+\sqrt{1.09520016}}{0.08}
$